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Proof step 4 from proof shiftright-rec-8-neg (previous step)

0 ≤ j, 0 < j, i < 0, 8 ≤ j, ∀ i, j0. i→n(j0) < i→n(j) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ i >> j = (i - 255) / 256 >> (j - 8)

User applied rule cut formula

And obtained the following new goals

Proof step 5:
j = 8, 0 ≤ j, 0 < j, i < 0, 8 ≤ j, ∀ i, j0. i→n(j0) < i→n(j) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ i >> j = (i - 255) / 256 >> (j - 8)
Proof step 26:
0 ≤ j, 0 < j, i < 0, 8 ≤ j, ∀ i, j0. i→n(j0) < i→n(j) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ j = 8, i >> j = (i - 255) / 256 >> (j - 8)

Rule argument

fma: j = 8

Additional information

Used formulas: j = 8