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Proof step 62 from proof shiftright-rec-8-neg (previous step)

j0 < 0 ∧ j0 % 2 = 0, j0 * 128 = j1 * 256, j1 * 256 >> (j - 1) = j1 >> (j - 9), j0 < 0, 0 < j, 8 < j, ∀ i, j0. i→n(j0) < i→n(j) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ j = 0, j1 >> (j - 9) = j0 / 2 >> (j - 9), j = 8, j1 = j0 / 2

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ i % 2 = 0 → (i / 2 = j ↔ i = 2 * j);% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;%j ≠ 0, j0 % j = 0 ⊦ i * (* j) = i0 * (* j0) ↔ i = i0 * j0 / j;