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Proof step 66 from proof shiftright-rec-8-neg (previous step)

¬(j0 % 2 ≠ 0 ∧ 1 = 2 - 1 ∧ j0 < 0 ∧ 0 < 2), j0 * 128 >> (j - 1) = (j0 / 2 - 1) >> (j - 9), 8 < j, 0 < j, j0 < 0, ∀ i, j0. i→n(j0) < i→n(j) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ j = 8, j0 * 128 >> (j - 1) = (j0 - 1) / 2 >> (j - 9), j = 0, j0 / 2 = (j0 - 1) / 2 + 1, (j0 * 128) % 256 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 67:
j0 * 128 >> (j - 1) = (j0 / 2 - 1) >> (j - 9), j0 % 2 = 0, 8 < j, 0 < j, j0 < 0, ∀ i, j0. i→n(j0) < i→n(j) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ (j0 * 128) % 256 = 0, j = 8, j0 * 128 >> (j - 1) = j0 / 2 >> (j - 9), j = 0, j0 = 2 * (1 + j0 / 2)

Rule argument

Additional information

Used simplifier rules: ⊦ i % 2 = 0 → (i / 2 = j ↔ i = 2 * j);% ⊦ i < 0 ∧ i % 2 = 0 → (i - 1) / 2 = i / 2;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ¬ i < j ↔ j ≤ i;