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Proof step 8 from proof shiftright-rec-8-neg (previous step)

¬(i < ~(2 ^ (abs(8) - 1)) ∧ 8 ≠ 0), i < 0, ∀ i, j0. i→n(j0) < i→n(8) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ i >> 8 = (i - 255) / 256

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
i < 0, ~128 ≤ i, ∀ i, j0. i→n(j0) < i→n(8) → 8 ≤ j0 ∧ i < 0 ∧ 0 < j0 ∧ 0 ≤ j0 → i >> j0 = (i - 255) / 256 >> (j0 - 8) ⊦ i >> 8 = (i - 255) / 256

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)% ⊦ ¬ i < j ↔ j ≤ i;