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Proof step 12 from proof shiftright-rec-8 (
previous step
)
0 ≤ i0 ∧ 0 ≤ 8, 0 ≤ i, 0 ≤ i0 ⊦ i / (2 ^ i0 * 2 ^ 8) = (i / 256) / 2 ^ i0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 13
:
0 ≤ i, 0 ≤ i0 ⊦ i / (256 * 2 ^ i0) = (i / 256) / 2 ^ i0
Rule argument
Additional information