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Proof step 13 from proof shiftright-rec-neg (previous step)

~1 + 1 = 0 ⊦ j = 0, bits2int(sublist(0, # true ', mklist(true, i→n(j)) + true ')) = bits2int(sublist(0, # true ', mklist(true, i→n(abs(j) - 1)) + true '))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
⊦ j = 0, bits2int(sublist(0, 1, mklist(true, i→n(j)) + true ')) = bits2int(sublist(0, 1, mklist(true, i→n(abs(j) - 1)) + true '))

Rule argument

Additional information

Used simplifier rules: ⊦ # boolvar ' = 0 +1;