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Proof step 16 from proof shiftright-rec-neg (previous step)

⊦ j = 0, bits2int(sublist(0, 1, mklist(true, i→n(j)) + true ')) = bits2int(firstn(1, restn(0, mklist(true, i→n(abs(j) - 1)) + true ')))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
⊦ j = 0, bits2int(sublist(0, 1, mklist(true, i→n(j)) + true ')) = bits2int(firstn(1, mklist(true, i→n(abs(j) - 1)) + true '))

Rule argument

Additional information

Used simplifier rules: ⊦ restn(0, bits) = bits;