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Proof step 19 from proof shiftright-rec-neg (previous step)

mklist(true, i→n(abs(j) - 1)) + true ' ≠ [] ⊦ j = 0, bits2int(sublist(0, 1, mklist(true, i→n(j)) + true ')) = bits2int((mklist(true, i→n(abs(j) - 1)) + true ').first ')

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
⊦ j = 0, bits2int(sublist(0, 1, mklist(true, i→n(j)) + true ')) = bits2int((mklist(true, i→n(abs(j) - 1)) + true ').first ')

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + boolvar ' ≠ [];