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Proof step 28 from proof shiftright-rec-neg (previous step)

i→n(j) ≠ 0 ⊦ j = 0, bits2int(true ') = bits2int((mklist(true, i→n(abs(j) - 1)) + true ').first ')

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
⊦ j = 0, ~1 = bits2int((mklist(true, i→n(abs(j) - 1)) + true ').first ')

Rule argument

Additional information

Used simplifier rules: ⊦ i→n(i) = 0 ↔ i = 0;% ⊦ bits2int(true ') = ~1;