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Proof step 5 from proof shiftright-rec-neg (previous step)

i < 0 ⊦ j = 0, bits2int(sublist(0, # int2bits(i), mklist(true, i→n(j)) + int2bits(i))) = (i - 1) / 2 >> (abs(j) - 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ i >> j = bits2int(sublist(0, # int2bits(i), mklist(int2bits(i).first, i→n(j)) + int2bits(i)))
Proof step 7:
i < 0 ⊦ j = 0, bits2int(sublist(0, # int2bits(i), mklist(true, i→n(j)) + int2bits(i))) = bits2int(sublist(0, # int2bits((i - 1) / 2), mklist(int2bits((i - 1) / 2).first, i→n(abs(j) - 1)) + int2bits((i - 1) / 2)))

Rule argument

name: shiftrsign-01 rotate: F subst: [j, i] → [abs(j) - 1, (i - 1) / 2]

Additional information

Used terms: abs(j) - 1, (i - 1) / 2