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Proof step 45 from proof shiftright-rec-pos (previous step)

mklist(false, i→n(i0) - 1) + false ' + false ' + true ' = true ' + bits1, 0 < i0 ⊦ i0 = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 46:
i→n(i0) = m + 1 ∧ i→n(i0) ≠ 0, mklist(false, m) + false ' + false ' + true ' = true ' + bits1, 0 < i0 ⊦ i0 = 0

Rule argument

seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [i→n(i0), m] rotate: T spec: nat inst: name: elim-pred-c

Additional information

Used simplifier rules: ⊦ i→n(i) = 0 ↔ i = 0;%n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: i→n(i0), m