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Proof step 55 from proof shiftright-rec-pos (previous step)

¬ true ∈ firstn(1, mklist(false, i→n(i0)) + false ') ∧ firstn(1, mklist(false, i→n(i0)) + false ') ≠ [], 0 ≤ i0 ⊦ bits2int(firstn(1, mklist(false, i→n(i0)) + false ' + false ')) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 56:
0 ≤ i0 ⊦ bits2int(firstn(1, mklist(false, i→n(i0)) + false ' + false ')) = 0, true ∈ firstn(1, mklist(false, i→n(i0)) + false ')

Rule argument

Additional information

Used simplifier rules: ⊦ firstn(n, bits) = [] ↔ n = 0;