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Proof step 2 from proof shiftright-shift (previous step)

j + j0 < 32, 0 ≤ j, 0 ≤ j0 ⊦ (i >> j) >> j0 = i >> (j + j0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i ∧ 0 ≤ j → i >> j = i / 2 ^ j
Proof step 4:
¬(0 ≤ i ∧ 0 ≤ j + j0), j + j0 < 32, 0 ≤ j, 0 ≤ j0 ⊦ (i >> j) >> j0 = i >> (j + j0)
Proof step 22:
0 ≤ i ∧ 0 ≤ j + j0, j + j0 < 32, 0 ≤ j, 0 ≤ j0 ⊦ (i >> j) >> j0 = i / 2 ^ (j + j0)

Rule argument

name: shiftright-pos-div rotate: F subst: [j, i] → [j + j0, i]

Additional information

Used terms: j + j0, i