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Proof step 6 from proof shiftright-shift (previous step)

i < 0 ∧ 0 ≤ j0 ∧ 0 ≤ j ∧ j + j0 < 32, ∀ j0, i, j1. i→n(j1) < i→n(j) → i < 0 ∧ 0 ≤ j0 ∧ 0 ≤ j1 ∧ j1 + j0 < 32 → (i >> j1) >> j0 = i >> (j1 + j0) ⊦ (i >> j) >> j0 = i >> (j + j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
j + j0 < 32, 0 ≤ j, 0 ≤ j0, i < 0, ∀ j0, i, j1. i→n(j1) < i→n(j) → i < 0 ∧ 0 ≤ j0 ∧ 0 ≤ j1 ∧ j1 + j0 < 32 → (i >> j1) >> j0 = i >> (j1 + j0) ⊦ (i >> j) >> j0 = i >> (j + j0)

Proof step 6 from proof shiftright-shift (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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