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Proof step 8 from proof shiftright-shift (previous step)

j + j0 < 32, 0 ≤ j, 0 ≤ j0, i < 0, ∀ j0, i, j1. i→n(j1) < i→n(j) → i < 0 ∧ 0 ≤ j0 ∧ 0 ≤ j1 ∧ j1 + j0 < 32 → (i >> j1) >> j0 = i >> (j1 + j0) ⊦ j = 0, (i >> j) >> j0 = i >> (j + j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
0 ≤ j0, i < 0, j + j0 < 32, 0 < j, ∀ j0, i, j1. i→n(j1) < i→n(j) → i < 0 ∧ 0 ≤ j0 ∧ 0 ≤ j1 ∧ j1 + j0 < 32 → (i >> j1) >> j0 = i >> (j1 + j0) ⊦ j = 0, (i >> j) >> j0 = i >> (j + j0)

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i ≠ j → (i ≤ j ↔ i < j);