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Proof step 4 from proof shiftzero-by-one-01 (previous step)

i < ~1 ∧ n ≠ 0, i < ~1, i < 0 ⊦ n = 0, bits2uint(fillsgn(n -1, int2bits((i - 1) / 2))) = (i - 1) / 2 + 2 ^ n→i(# fillsgn(n, int2bits(i)) - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i < ~1, i < 0 ⊦ n = 0, bits2uint(fillsgn(n - 1, int2bits((i - 1) / 2))) = (i - 1) / 2 + 2 ^ n→i(# fillsgn(n, int2bits(i)) - 1)

Rule argument

Additional information

Used simplifier rules: ⊦ n -1 = n - 1;