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Proof step 9 from proof shiftzero-by-one (previous step)

n = m + 1, i < ~1, i < 0 ⊦ n = 0, bits2int(firstn(# fillsgn(n, int2bits(i)), false ' + fillsgn(n, int2bits(i)))) = bits2uint(fillsgn(m, int2bits((i - 1) / 2)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
i < ~1, i < 0 ⊦ bits2int(firstn(# fillsgn(m + 1, int2bits(i)), false ' + fillsgn(m + 1, int2bits(i)))) = bits2uint(fillsgn(m, int2bits((i - 1) / 2)))

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + 1 ≠ 0;