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Proof step 1 from proof shiftzero-max-neg-01 (conclusion)

⊦ i < 0 ∧ # int2bits(i) ≤ n ∧ j ≤ n→i(n) ∧ 0 < j ∧ n ≠ 0 → >>>(n, i, j) < 2 ^ (n→i(n) - j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < j, i < 0, 2 ^ (n→i(n) - j) ≤ >>>(n, i, j), j ≤ n→i(n), # int2bits(i) ≤ n ⊦ n = 0

Rule argument

Additional information

Used simplifier rules: ⊦ 0 < n ↔ n ≠ 0;%0 ≤ i ⊦ (* i) < n→i(n) ↔ i→n(i) < n;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ ¬ i < j ↔ j ≤ i;