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Proof step 24 from proof shiftzero-max-neg-01 (previous step)

j ≤ n→i(n), 0 < j, 1 ≤ n, 2 ^ (n→i(n) - j) < 2 ^ n→i(n) / 2 ^ j, ∀ n, i, j0. i→n(j0) < i→n(j) → 0 < j0 ∧ i < 0 ∧ 2 ^ (n→i(n) - j0) ≤ >>>(n, i, j0) ∧ j0 ≤ n→i(n) ∧ # int2bits(i) ≤ n → n = 0 ⊦ j = 0, n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ 0 ≤ j0 ∧ j0 ≤ j ∧ i ≠ 0 → i ^ (j - j0) = i ^ j / i ^ j0 subst: [j0, j, i] → [j, n→i(n), 2] rotate: F spec: int-pot inst: name: pot-sub-dist

Additional information

Used simplifier rules: ⊦ ¬ i < i;% ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → ¬ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: j, n→i(n), 2