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Proof step 40 from proof shiftzero-max-neg-01 (previous step)

n - 1 = 0, 0 < j, 1 < j, 2 ^ (n→i(n) - j) ≤ >>>(0, (i - 1) / 2, j - 1), j ≤ n→i(n), # int2bits(i) ≤ n, i < ~1, i < 0, ∀ n, i, j0. i→n(j0) < i→n(j) → 0 < j0 ∧ i < 0 ∧ 2 ^ (n→i(n) - j0) ≤ >>>(n, i, j0) ∧ j0 ≤ n→i(n) ∧ # int2bits(i) ≤ n → n = 0 ⊦ n = 0, n = 1

User applied rule insert elim lemma

And closed the goal!

Rule argument

seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [n, m] rotate: T spec: nat inst: name: elim-pred-c

Additional information

Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: n, m