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Proof step 11 from proof shiftzero-max-neg (previous step)

# int2bits(~1) ≤ n, 2 ^ (n→i(n) - 1) ≤ >>>(n, ~1, j), 0 < j, ∀ n, i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ # int2bits(i) ≤ n ∧ 0 < j0 ∧ n ≠ 0 → >>>(n, i, j0) < 2 ^ (n→i(n) - 1) ⊦ n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ i + 1 = 0 → int2bits(i) = true '
Proof step 13:
~1 + 1 = 0, # true ' ≤ n, 2 ^ (n→i(n) - 1) ≤ >>>(n, ~1, j), 0 < j, ∀ n, i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ # int2bits(i) ≤ n ∧ 0 < j0 ∧ n ≠ 0 → >>>(n, i, j0) < 2 ^ (n→i(n) - 1) ⊦ n = 0

Rule argument

seq: ⊦ i + 1 = 0 → int2bits(i) = true ' subst: [i] → [~1] rotate: F spec: int2bits inst: name: int2bits-mone

Additional information

Used terms: ~1