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Proof step 16 from proof shiftzero-max-neg (previous step)

j ≠ 0 ∧ n ≠ 0, 2 ^ (n→i(n) - 1) ≤ (2 ^ n→i(n) - 1) >> j, 0 < j, 1 ≤ n, ∀ n, i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ # int2bits(i) ≤ n ∧ 0 < j0 ∧ n ≠ 0 → >>>(n, i, j0) < 2 ^ (n→i(n) - 1) ⊦ n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
1 ≤ n, 0 < j, 2 ^ (n→i(n) - 1) ≤ (2 ^ n→i(n) - 1) >> j, ∀ n, i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ # int2bits(i) ≤ n ∧ 0 < j0 ∧ n ≠ 0 → >>>(n, i, j0) < 2 ^ (n→i(n) - 1) ⊦ j = 0, n = 0

Proof step 16 from proof shiftzero-max-neg (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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