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Proof step 20 from proof shiftzero-max-neg (previous step)

1 ≤ n, 0 < j, 2 ^ (n→i(n) - 1) ≤ (2 ^ n→i(n) - 1) / 2 >> (j - 1), ∀ n, i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ # int2bits(i) ≤ n ∧ 0 < j0 ∧ n ≠ 0 → >>>(n, i, j0) < 2 ^ (n→i(n) - 1) ⊦ j = 0, n = 0

User applied rule insert elim lemma

And obtained the following new goals

Proof step 21:
n→i(n) = i0 + 1, 1 ≤ n, 0 < j, 2 ^ i0 ≤ (2 ^ n→i(n) - 1) / 2 >> (j - 1), ∀ n, i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ # int2bits(i) ≤ n ∧ 0 < j0 ∧ n ≠ 0 → >>>(n, i, j0) < 2 ^ (n→i(n) - 1) ⊦ j = 0, n = 0

Rule argument

seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [n→i(n), 1, i0] rotate: T spec: int-abs inst: name: elim-sub

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: n→i(n), 1, i0