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Proof step 39 from proof shiftzero-max-neg (previous step)

i < ~1 ∧ # int2bits(i) ≤ n ∧ 1 < j, # int2bits(i) ≤ n, 2 ^ (n→i(n) - 1) ≤ >>>(n -1, (i - 1) / 2, j - 1), i < 0, 0 < j, ∀ n, i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ # int2bits(i) ≤ n ∧ 0 < j0 ∧ n ≠ 0 → >>>(n, i, j0) < 2 ^ (n→i(n) - 1) ⊦ n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 40:
i < 0, i < ~1, # int2bits(i) ≤ n, 2 ^ (n→i(n) - 1) ≤ >>>(n - 1, (i - 1) / 2, j - 1), 1 < j, 0 < j, ∀ n, i, j0. i→n(j0) < i→n(j) → true → i < 0 ∧ # int2bits(i) ≤ n ∧ 0 < j0 ∧ n ≠ 0 → >>>(n, i, j0) < 2 ^ (n→i(n) - 1) ⊦ n = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ n -1 = n - 1;