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Proof step 12 from proof shiftzero-minus-one (previous step)

⊦ j = 0, n = 0, bits2int(firstn(# fillsgn(n, int2bits(~1)), restn(0, mklist(false, i→n(j)) + fillsgn(n, int2bits(~1))))) = bits2int(firstn(1 + n, mklist(false, i→n(j)) + false ' + mklist(true, n)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
⊦ j = 0, n = 0, bits2int(firstn(# fillsgn(n, int2bits(~1)), mklist(false, i→n(j)) + fillsgn(n, int2bits(~1)))) = bits2int(firstn(1 + n, mklist(false, i→n(j)) + false ' + mklist(true, n)))

Rule argument

Additional information

Used simplifier rules: ⊦ restn(0, bits) = bits;