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Proof step 2 from proof shiftzero-minus-one (previous step)

⊦ j = 0, n = 0, >>>(n, ~1, j) = (2 ^ n→i(n) - 1) >> j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ >>>(n, i, j) = bits2int(sublist(0, # fillsgn(n, int2bits(i)), mklist(false, i→n(j)) + fillsgn(n, int2bits(i))))
Proof step 4:
⊦ j = 0, n = 0, bits2int(sublist(0, # fillsgn(n, int2bits(~1)), mklist(false, i→n(j)) + fillsgn(n, int2bits(~1)))) = (2 ^ n→i(n) - 1) >> j

Rule argument

name: shiftrzero-def-01 rotate: F subst: [j, i, n] → [j, ~1, n]

Additional information

Used terms: j, ~1, n