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Proof step 21 from proof shiftzero-minus-one (previous step)

⊦ j = 0, bits2int(firstn(n, mklist(false, i→n(j)) + mklist(true, n))) = bits2int(firstn(1 + n, false ' + mklist(false, i→n(j)) + mklist(true, n))), n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
⊦ n = 0, j = 0, bits2int(firstn(n, mklist(false, i→n(j)) + mklist(true, n))) = bits2uint(firstn(n, mklist(false, i→n(j)) + mklist(true, n)))

Rule argument

Additional information

Used simplifier rules: ⊦ bits2int(false ' + bits) = bits2uint(bits);% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar + bits = boolvar ' + bits;% ⊦ firstn(n + 1, boolvar ' + bits) = boolvar + firstn(n, bits);