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Proof step 24 from proof shiftzero-minus-one (previous step)

¬(¬ firstn(n, mklist(false, i→n(j)) + mklist(true, n)).first ∧ firstn(n, mklist(false, i→n(j)) + mklist(true, n)) ≠ []) ⊦ n = 0, j = 0, bits2int(firstn(n, mklist(false, i→n(j)) + mklist(true, n))) = bits2uint(firstn(n, mklist(false, i→n(j)) + mklist(true, n)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
firstn(n, mklist(false, i→n(j)) + mklist(true, n)).first ⊦ n = 0, j = 0, bits2int(firstn(n, mklist(false, i→n(j)) + mklist(true, n))) = bits2uint(firstn(n, mklist(false, i→n(j)) + mklist(true, n)))

Rule argument

Additional information

Used simplifier rules: ⊦ firstn(n, bits) = [] ↔ n = 0;