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Proof step 28 from proof shiftzero-minus-one (previous step)

(mklist(false, i→n(j)) + mklist(true, n)).first ⊦ n = 0, mklist(false, i→n(j)) + mklist(true, n) = [], bits2int(firstn(n, mklist(false, i→n(j)) + mklist(true, n))) = bits2uint(firstn(n, mklist(false, i→n(j)) + mklist(true, n))), j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 29:
⊦ n ≠ 0 → ((mklist(boolvar, n) + bits).first ↔ boolvar)

Rule argument

seq: ⊦ n ≠ 0 → ((mklist(boolvar, n) + bits).first ↔ boolvar) subst: [bits, n, boolvar] → [mklist(true, n), i→n(j), false] rotate: F spec: list-last inst: bitlista name: mk-first

Additional information

Used simplifier rules: ⊦ i→n(i) = 0 ↔ i = 0; Used terms: mklist(true, n), i→n(j), false