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Proof step 15 from proof shiftzero-not-neg (previous step)

# fillsgn(n, int2bits(i)) ≠ 0 ∧ mklist(false, i→n(j)) + fillsgn(n, int2bits(i)) ≠ [], i < 0, (mklist(false, i→n(j)) + fillsgn(n, int2bits(i))).first ⊦ j = 0, fillsgn(n, int2bits(i)) = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
i < 0, (mklist(false, i→n(j)) + fillsgn(n, int2bits(i))).first ⊦ j = 0, fillsgn(n, int2bits(i)) = [], mklist(false, i→n(j)) + fillsgn(n, int2bits(i)) = []

Rule argument

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];