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Proof step 15 from proof shiftzero-pos (previous step)

¬ n ≤ # int2bits(i), 0 ≤ i ⊦ bits2int(firstn(# fillsgn(n, int2bits(i)), mklist(false, i→n(j)) + fillsgn(n, int2bits(i)))) = bits2int(firstn(# int2bits(i), mklist(false, i→n(j)) + int2bits(i)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0;% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;