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Proof step 18 from proof shiftzero-pos (previous step)

# int2bits(i) ≤ n, # int2bits(i) < n, 0 ≤ i ⊦ bits2int(firstn(n, mklist(false, i→n(j)) + fillsgn(n, int2bits(i)))) = bits2int(firstn(# int2bits(i), mklist(false, i→n(j)) + int2bits(i)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → m ≤ n;