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Proof step 35 from proof shiftzero-pos (previous step)

¬ n ≤ # mklist(false, i→n(j) + (n - # int2bits(i))), # int2bits(i) < i→n(j), 0 ≤ i, # int2bits(i) < n ⊦ j = 0, bits2int(firstn(n, mklist(false, i→n(j) + (n - # int2bits(i))) + int2bits(i))) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 36:
# int2bits(i) < i→n(j), 0 ≤ i, # int2bits(i) < n, i→n(j) + (n - # int2bits(i)) < n ⊦ j = 0, bits2int(firstn(n, (mklist(false, i→n(j)) + mklist(false, n - # int2bits(i))) + int2bits(i))) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # mklist(boolvar, n) = n;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ mklist(boolvar, m + n) = mklist(boolvar, m) + mklist(boolvar, n);