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Proof step 53 from proof shiftzero-pos (previous step)

i→n(j) ≠ 0, # int2bits(i) = i→n(j), 0 ≤ i, i→n(j) < n ⊦ bits2int(firstn(n, mklist(false, i→n(j)) + mklist(false, n - i→n(j)) + int2bits(i))) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 54:
# int2bits(i) = i→n(j), 0 ≤ i, i→n(j) < n ⊦ bits2int(firstn(n, mklist(false, i→n(j)) + mklist(false, n - i→n(j)) + int2bits(i))) = 0, j = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i→n(i) = 0 ↔ i = 0;