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Proof step 62 from proof shiftzero-pos (previous step)

# int2bits(i) = i→n(j), 0 ≤ i, i→n(j) < n ⊦ mklist(false, i→n(j)) + mklist(false, n - i→n(j)) + int2bits(i) = mklist(false, n) + int2bits(i), bits2int(firstn(n, mklist(false, i→n(j)) + mklist(false, n - i→n(j)) + int2bits(i))) = 0, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 63:
# int2bits(i) = i→n(j), 0 ≤ i, i→n(j) < n ⊦ bits2int(firstn(n, mklist(false, i→n(j)) + mklist(false, n - i→n(j)) + int2bits(i))) = 0, j = 0, mklist(false, i→n(j)) + mklist(false, n - i→n(j)) = mklist(false, n)

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + bits0 = bits1 + bits0 ↔ bits = bits1;