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Proof step 75 from proof shiftzero-pos (previous step)

¬ # mklist(false, n - # int2bits(i)) ≤ n - i→n(j), i→n(j) < # int2bits(i), 0 ≤ i, # int2bits(i) < n, i→n(j) < n, i→n(j) + 1 < n ⊦ # int2bits(i) = i→n(j), bits2int(mklist(false, i→n(j)) + firstn(n - i→n(j), mklist(false, n - # int2bits(i)) + int2bits(i))) = bits2int(firstn(# int2bits(i) - i→n(j), int2bits(i))), firstn(# int2bits(i) - i→n(j), int2bits(i)).first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 76:
i→n(j) < # int2bits(i), 0 ≤ i, # int2bits(i) < n, i→n(j) < n, i→n(j) + 1 < n, (n - i→n(j)) + # int2bits(i) < n ⊦ # int2bits(i) = i→n(j), bits2int(mklist(false, i→n(j)) + firstn(n - i→n(j), mklist(false, n - # int2bits(i)) + int2bits(i))) = bits2int(firstn(# int2bits(i) - i→n(j), int2bits(i))), firstn(# int2bits(i) - i→n(j), int2bits(i)).first

Rule argument

Additional information

Used simplifier rules: n0 ≤ n ⊦ n - n0 ≤ m ↔ n ≤ m + n0;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < n → ¬ n < m;% ⊦ # mklist(boolvar, n) = n;