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Proof step 17 from proof shiftzero-rec-neg-longer (previous step)

n ≤ #(int2bits((i - 1) / 2) + (i % 2 ≠ 0)'), i < ~1, 0 < j, 1 < j, i < 0, n ≤ # int2bits((i - 1) / 2) ⊦ i = ~1, bits2int(firstn(#(int2bits((i - 1) / 2) + (i % 2 ≠ 0)'), mklist(false, i→n(j)) + int2bits((i - 1) / 2) + (i % 2 ≠ 0)')) = bits2int(firstn(# int2bits((i - 1) / 2), mklist(false, i→n(j) - 1) + int2bits((i - 1) / 2)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
i < ~1, 0 < j, 1 < j, i < 0, n ≤ # int2bits((i - 1) / 2), n ≤ # int2bits((i - 1) / 2) + 1 ⊦ i = ~1, bits2int(firstn(# int2bits((i - 1) / 2) + 1, mklist(false, i→n(j)) + int2bits((i - 1) / 2) + (i % 2 ≠ 0)')) = bits2int(firstn(# int2bits((i - 1) / 2), mklist(false, i→n(j) - 1) + int2bits((i - 1) / 2)))

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;