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Proof step 23 from proof shiftzero-rec-neg-shorter (previous step)

i→n(j) = m0 + 1, # int2bits((i - 1) / 2) ≤ m, i < ~1, # int2bits(i) ≤ m + 1, i < 0, 1 < j, 0 < j ⊦ bits2int(firstn(m + 1, mklist(false, m0 + 1) + fillsgn(m + 1, int2bits(i)))) = bits2int(firstn(m, mklist(false, m0) + fillsgn(m, int2bits((i - 1) / 2)))), j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 24:
⊦ m ≠ 0 → mklist(boolvar, m) = boolvar + mklist(boolvar, m - 1)
Proof step 25:
m0 + 1 ≠ 0, i→n(j) = m0 + 1, # int2bits((i - 1) / 2) ≤ m, i < ~1, # int2bits(i) ≤ m + 1, i < 0, 1 < j, 0 < j ⊦ bits2int(firstn(m + 1, (false + mklist(false, m0 + 1 - 1)) + fillsgn(m + 1, int2bits(i)))) = bits2int(firstn(m, mklist(false, m0) + fillsgn(m, int2bits((i - 1) / 2)))), j = 0

Rule argument

seq: ⊦ m ≠ 0 → mklist(boolvar, m) = boolvar + mklist(boolvar, m - 1) subst: [m, boolvar] → [m0 + 1, false] rotate: F spec: list-last inst: bitlista name: mk-rec

Additional information

Used simplifier rules: ⊦ m + 1 ≠ 0;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m; Used terms: m0 + 1, false