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Proof step 35 from proof shiftzero-rec-neg-shorter (previous step)

i→n(j) = m0 + 1, # int2bits((i - 1) / 2) ≤ m, i < ~1, i < 0, 1 < j, 0 < j ⊦ i = ~1, j = 0, bits2uint(firstn(m, mklist(false, m0) + mklist(true, m - # int2bits((i - 1) / 2)) + int2bits((i - 1) / 2))) = bits2int(firstn(m, mklist(false, m0) + mklist(true, m - # int2bits((i - 1) / 2)) + int2bits((i - 1) / 2)))

User applied rule cut formula

And obtained the following new goals

Proof step 36:
i→n(j) = m0 + 1, # int2bits((i - 1) / 2) ≤ m, i < ~1, i < 0, 1 < j, 0 < j ⊦ m0 = 0, i = ~1, j = 0, bits2uint(firstn(m, mklist(false, m0) + mklist(true, m - # int2bits((i - 1) / 2)) + int2bits((i - 1) / 2))) = bits2int(firstn(m, mklist(false, m0) + mklist(true, m - # int2bits((i - 1) / 2)) + int2bits((i - 1) / 2)))

Rule argument

fma: m0 = 0

Additional information

Used simplifier rules: ⊦ i ≠ j → (i ≤ j ↔ i < j);%0 ≤ i ⊦ i→n(i) = (* m) ↔ i = n→i(m);% ⊦ mklist(boolvar, 0) = [];% ⊦ [] + bits = bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used formulas: m0 = 0