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Proof step 1 from proof shiftzero-zero-size-01 (conclusion)

⊦ i < 0 ∧ j ≠ 0 → >>>(0, i, j) = (2 ^ n→i(# int2bits(i)) + i) >> j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i < 0 ⊦ >>>(0, i, j) = (2 ^ n→i(# int2bits(i)) + i) >> j, j = 0

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)