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Proof step 30 from proof shiftzero-zero-size (previous step)

i < 0 ⊦ mklist(false, i→n(j)) + false ' + int2bits(i) = false ' + mklist(false, i→n(j)) + int2bits(i), j = 0, bits2int(firstn(# int2bits(i), mklist(false, i→n(j)) + int2bits(i))) = bits2int(firstn(1 + # int2bits(i), mklist(false, i→n(j)) + false ' + int2bits(i)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 31:
i < 0 ⊦ j = 0, bits2int(firstn(# int2bits(i), mklist(false, i→n(j)) + int2bits(i))) = bits2int(firstn(1 + # int2bits(i), mklist(false, i→n(j)) + false ' + int2bits(i))), mklist(false, i→n(j)) + false ' = false ' + mklist(false, i→n(j))

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + bits0 = bits1 + bits0 ↔ bits = bits1;