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Proof step 6 from proof shiftzero-zero-size (previous step)

⊦ j = 0, bits2int(sublist(0, # int2bits(i), mklist(false, i→n(j)) + int2bits(i))) = bits2int (sublist(0, # int2bits(bits2uint(int2bits(i))), mklist(int2bits(bits2uint(int2bits(i))).first, i→n(j)) + int2bits(bits2uint(int2bits(i)))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ bits2uint(bits) < 0;% ⊦ int2bits(j).first ↔ j < 0;