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Proof step 2 from proof prod-eq-one (previous step)

Π nats = 1, m < # nats ⊦ nats[m] = 1, nats = []

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ Π nats = 1 ∧ m ∈ nats → m = 1

Rule argument

name: prod-eq-one-01 subst: [nats, m] → [nats, nats[m]]

Additional information

Used simplifier rules: ⊦ m < # nats → (¬ nats[m] ∈ nats ↔ false); Used terms: nats, nats[m]