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Proof step 3 from proof sum-append (previous step)

∀ nats0. Σ(nats1 + nats0) = Σ nats1 + Σ nats0 ⊦ Σ(nats1 + nats0) = Σ nats0 + Σ nats1

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: nats0

Additional information

Used simplifier rules: ⊦ m + n = n + m; Used terms: nats0