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Proof step 27 from proof Extsimple (previous step)

i1 / gcd(i1, j1) = i2 / gcd(i2, j2), j1 / gcd(i1, j1) = j2 / gcd(i2, j2), i1 < 0, j1 < 0, 0 < i2, j2 < 0 ⊦ i1 = 0, i2 = 0, j1 = 0, j2 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 28:
i1 / gcd(i1, j1) < 0, i1 / gcd(i1, j1) = i2 / gcd(i2, j2), j1 / gcd(i1, j1) = j2 / gcd(i2, j2), i1 < 0, j1 < 0, 0 < i2, j2 < 0 ⊦ i1 = 0, i2 = 0, j1 = 0, j2 = 0

Rule argument

fma: i1 / gcd(i1, j1) < 0

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i0 < 0 → ¬ 0 ≤ i0 / gcd(i, i0);% ⊦ gcd(i, j) = gcd(j, i); Used formulas: i1 / gcd(i1, j1) < 0