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Proof step 39 from proof Extsimple (previous step)

i1 / gcd(i1, j1) < 0, j1 / gcd(i1, j1) = j2 / gcd(i2, j2), i1 / gcd(i1, j1) = i2 / gcd(i2, j2), 0 < i1, j1 < 0, j2 < 0, i2 < 0 ⊦ i1 = 0, i2 = 0, j1 = 0, j2 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 40:
j1 / gcd(i1, j1) = j2 / gcd(i2, j2), i1 / gcd(i1, j1) = i2 / gcd(i2, j2), 0 < i1, j1 < 0, j2 < 0, i2 < 0, i2 / gcd(i2, j2) < 0 ⊦ i1 = 0, i2 = 0, j1 = 0, j2 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)