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Proof step 60 from proof Extsimple (previous step)

j2 / gcd(i2, j2) + j1 / gcd(i1, j1) = 0, i2 / gcd(i2, j2) + i1 / gcd(i1, j1) = 0, 0 < j1, j2 < 0, 0 < i2, 0 < i1 ⊦ j2 = 0, j1 = 0, i2 = 0, i1 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 61:
⊦ 0 < i ∧ 0 < j → i + j ≠ 0

Rule argument

seq: ⊦ 0 < i ∧ 0 < j → i + j ≠ 0 subst: [j, i] → [i1 / gcd(i1, j1), i2 / gcd(i2, j2)] rotate: F spec: int-basic2 inst: name: not-zero-pos

Additional information

Used simplifier rules: ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ 0 < i → ¬ i / gcd(i, i0) ≤ 0; Used terms: i1 / gcd(i1, j1), i2 / gcd(i2, j2)