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Proof step 94 from proof Extsimple (previous step)

i2 ≠ 0 ∧ 0 < j2, abs(i1) / gcd(i1, j1) = abs(i2) / gcd(i2, j2), j1 / gcd(i1, j1) = abs(j2) / gcd(i2, j2), 0 < j1, 0 < i1 ∧ (0 < i2 ∧ 0 < j2 ∨ i2 < 0 ∧ j2 < 0) ∨ i1 < 0 ∧ (0 < i2 ∧ j2 < 0 ∨ i2 < 0 ∧ 0 < j2) ⊦ j2 = 0, j1 = 0, i2 = 0, i1 / gcd(i1, j1) = i2 / gcd(i2, j2), i1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 95:
abs(i1) / gcd(i1, j1) = abs(i2) / gcd(i2, j2), j1 / gcd(i1, j1) = j2 / gcd(i2, j2), 0 < j1, 0 < j2, 0 < i1 ∧ 0 < i2 ∨ i1 < 0 ∧ i2 < 0 ⊦ j2 = 0, j1 = 0, i1 / gcd(i1, j1) = i2 / gcd(i2, j2), i1 = 0, i2 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i < j → ¬ j < i;% ⊦ 0 < j → abs(j) = j;