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Proof step 1 from proof abs-num (conclusion)
⊦ abs(rj).num = abs(rj.num)
User applied rule structural induction
And obtained the following new goals
Proof step 2
:
⊦ abs(rational(i, i0)).num = abs(rational(i, i0).num)
Rule argument
indvar: rj
Additional information
Used simplifier rules: gen: ⊦ ;