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Proof step 18 from proof abs-pos (previous step)

0 < j ⊦ i = 0, j = 0, abs(rational(i, j)).num = rational(abs(i), j).num ∧ j / gcd(i, j) = j / gcd(i, j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information